From ad75542cbd06539ed9d45f0dfd051dad3d99af1c Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?J=E6=A2=A6=E6=9E=97?= <2777141796@qq.com>
Date: Wed, 14 Apr 2021 19:34:07 +0800
Subject: [PATCH] =?UTF-8?q?=E5=85=AB=E5=98=8E=E9=9B=85=E9=B9=BF?=
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---
 Ml01.java | 53 +++++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 53 insertions(+)
 create mode 100644 Ml01.java

diff --git a/Ml01.java b/Ml01.java
new file mode 100644
index 0000000..c0d0b89
--- /dev/null
+++ b/Ml01.java
@@ -0,0 +1,53 @@
+import java.util.Scanner;
+
+public class Ml01 {
+
+	public static void main(String[] args) {
+		//-   需求：在编程竞赛中，有6个评委为参赛的选手打分，分数为0-100的整数分。
+      //  选手的最后得分为：去掉一个最高分和一个最低分后 的4个评委平均值 (不考虑小数部分)。
+
+//-   思路：
+//1.定义一个数组，用动态初始化完成数组元素的初始化，长度为6
+//2.键盘录入评委分数
+//3.由于是6个评委打分，所以，接收评委分数的操作，用循环
+//4.求出数组最大值
+//5.求出数组最小值
+//6.求出数组总和
+//7.按照计算规则进行计算得到平均分
+//8.输出平均分
+		
+
+		Scanner scan = new Scanner(System.in);
+		
+		int [] age = new int[6];
+		 int sum  = 0;
+		
+		System.out.println("请输入评委给的我分数" );
+		
+		for(int i =0 ; i<age.length; i++) {
+			System.out.println("第"+(i+1)+"个评委给出的分数为" );
+			age[i] = scan.nextInt();
+	
+		}
+		int max = age[0];
+		int min =age[0];
+			for(int i =1 ; i<age.length; i++) {
+				if( age[i]>max ) {
+					max=age[i];
+					
+			}
+				if( age[i]<min) {
+					min =age[i];
+				}
+		}
+			for(int i =0 ; i<age.length; i++) {
+				sum +=age[i];
+			}
+			int avg =sum/age.length;
+			System.out.println("最高分为"+max );
+			System.out.println("最低分为"+min );
+			System.out.println("总分为"+sum );
+			System.out.println("平均分"+avg);
+	}
+
+}
-- 
Gitee