[Bug]: The test case of the partial utility type is incorrect.

原值

### 发生了什么问题？

Partial Utility Type 的测试用例错误

### 期望行为是什么？

..

### 如何复现该缺陷

..

### 其他补充信息

### 版本或分支信息

- [x] master

- [ ] 5.0-Beta1

- [ ] Release 4.1

- [ ] Release 4.0

- [ ] Release 3.2

新值

### 发生了什么问题？

Type Partial<T> constructs a type with all properties of T set to optional.

No matter whether there is an initial value in T, all fields that are not passed in during construction should be undefined.The same goes for TS.

Currently, when writing Partial test cases

1. The default value is 0 for fields of the int/number type.

```

interface{

    i: number;

    j: string;

}

function foo(i:Partial<T>){

    let v: int = 0;

 if (i.j != null) {

        v += 1;

   }

  if (i.i != 0) {

     v += 2;

  }

  return v;

}

function main(){

    assert(foo({i: 1.9, j: "some str"}) == 3)

    assert(foo({i: 1.9}) == 2)

    assert(foo({j: "some str"}) == 1) // The returned result should be 3.

    assert(foo({}) == 0) // The returned result should be 2.

}

```

2. The field initialized in T is regarded as the initialized value by default.

```

class{

    i: number = 0;

    j: string;

}

function foo(i:Partial<T>){

    let v: int = 0;

    if (i.j != null) {

        v += 1;

    }

    if (i.i != 0) {

        v += 2;

    }

    return v;

}

function main(){

    assert(foo({i: 1.9, j: "some str"}) == 3)

    assert(foo({i: 1.9}) == 2)

    assert(foo({j: "some str"}) == 1) // The returned result should be 3.

    assert(foo({}) == 0) // The returned result should be 2.

}

```

### 期望行为是什么？

..

### 如何复现该缺陷

..

### 其他补充信息

### 版本或分支信息

- [x] master

- [ ] 5.0-Beta1

- [ ] Release 4.1

- [ ] Release 4.0

- [ ] Release 3.2

原值

[Bug]: Partial Utility type 测试用例错误

新值

[Bug]: The test case of the partial utility type is incorrect.

原值

### 发生了什么问题？

Type Partial<T> constructs a type with all properties of T set to optional.

No matter whether there is an initial value in T, all fields that are not passed in during construction should be undefined.The same goes for TS.

Currently, when writing Partial test cases

1. The default value is 0 for fields of the int/number type.

```

interface{

    i: number;

    j: string;

}

function foo(i:Partial<T>){

    let v: int = 0;

    if (i.j != null) {

        v += 1;

    }

    if (i.i != 0) {

        v += 2;

    }

    return v;

}

function main(){

    assert(foo({i: 1.9, j: "some str"}) == 3)

    assert(foo({i: 1.9}) == 2)

    assert(foo({j: "some str"}) == 1) // The returned result should be 3.

    assert(foo({}) == 0) // The returned result should be 2.

}

```

2. The field initialized in T is regarded as the initialized value by default.

```

class{

    i: number = 0;

    j: string;

}

function foo(i:Partial<T>){

    let v: int = 0;

    if (i.j != null) {

        v += 1;

    }

    if (i.i != 0) {

        v += 2;

    }

    return v;

}

function main(){

    assert(foo({i: 1.9, j: "some str"}) == 3)

    assert(foo({i: 1.9}) == 2)

    assert(foo({j: "some str"}) == 1) // The returned result should be 3.

    assert(foo({}) == 0) // The returned result should be 2.

}

```

### 期望行为是什么？

..

### 如何复现该缺陷

..

### 其他补充信息

### 版本或分支信息

- [x] master

- [ ] 5.0-Beta1

- [ ] Release 4.1

- [ ] Release 4.0

- [ ] Release 3.2

新值

### 发生了什么问题？

Type Partial<T> constructs a type with all properties of T set to optional.

No matter whether there is an initial value in T, all fields that are not passed in during construction should be undefined.The same goes for TS.

Currently, when writing Partial test cases

1. The default value is 0 for fields of the int/number type.

```

interface{

    i: number;

    j: string;

}

function foo(i:Partial<T>){

    let v: int = 0;

    if (i.j != null) {

        v += 1;

    }

    if (i.i != 0) {

        v += 2;

    }

    return v;

}

function main(){

    assert(foo({i: 1.9, j: "some str"}) == 3)

    assert(foo({i: 1.9}) == 2)

    assert(foo({j: "some str"}) == 1) // The returned result should be 3.

    assert(foo({}) == 0) // The returned result should be 2.

}

```

2. The field initialized in T is regarded as the initialized value by default.

```

class{

    i: number = 0;

    j: string;

}

function foo(i:Partial<T>){

    let v: int = 0;

    if (i.j != null) {

        v += 1;

    }

    if (i.i != 0) {

        v += 2;

    }

    return v;

}

function main(){

    assert(foo({i: 1.9, j: "some str"}) == 3)

    assert(foo({i: 1.9}) == 2)

    assert(foo({j: "some str"}) == 1) // The returned result should be 3.

    assert(foo({}) == 0) // The returned result should be 2.

}

```

### 期望行为是什么？

The test case method return value should conform to the specification

### 如何复现该缺陷

Use the appeal test file

### 其他补充信息

### 版本或分支信息

- [x] master

- [] 5.0-Beta1

- [ ] Release 4.1

- [ ] Release 4.0

- [ ] Release 3.2

OpenHarmony/arkcompiler_runtime_core

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