26.汇总各个部门当前员工的title类型的分配数目.md · Henray0607/数据库SQL实战

# 汇总各个部门当前员工的title类型的分配数目

## 题目描述

汇总各个部门当前员工的title类型的分配数目，结果给出部门编号dept_no、dept_name、其当前员工所有的title以及该类型title对应的数目count

```mysql
CREATE TABLE `departments` (
`dept_no` char(4) NOT NULL,
`dept_name` varchar(40) NOT NULL,
PRIMARY KEY (`dept_no`));
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE IF NOT EXISTS `titles` (
`emp_no` int(11) NOT NULL,
`title` varchar(50) NOT NULL,
`from_date` date NOT NULL,
`to_date` date DEFAULT NULL);
```

## 答案

```mysql
select d.dept_no,d.dept_name,title,count(emp_no) count from (select emp_no,d.dept_no,title,dept_name from (select de.emp_no,dept_no,title from dept_emp de,titles t where de.emp_no = t.emp_no and t.to_date = '9999-01-01' and de.to_date = '9999-01-01') t1,departments d where t1.dept_no = d.dept_no) t1,departments d where t1.dept_no = d.dept_no group by t1.dept_no,title
```

## 题解

1、当前员工对用的title

```mysql
select de.emp_no,dept_no,title from dept_emp de,titles t where de.emp_no = t.emp_no and t.to_date = '9999-01-01' and de.to_date = '9999-01-01'
```

2、当前员工对应的dept信息

```mysql
select emp_no,d.dept_no,title,dept_name from (select de.emp_no,dept_no,title from dept_emp de,titles t where de.emp_no = t.emp_no and t.to_date = '9999-01-01' and de.to_date = '9999-01-01') t1,departments d where t1.dept_no = d.dept_no
```

3、罗列title对应的count，对dept_no和title进行分组

Henray0607/数据库SQL实战

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